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python 实现计算器功能 输入字符串,输出相应结果
阅读量:7163 次
发布时间:2019-06-29

本文共 1619 字,大约阅读时间需要 5 分钟。

import reformul='1 - 2 *( (6 0- 30+(0-40/5) * (9-2* 5/3 +7 /3*99/4*2998 +10 *568/14)) - (-4*3) / (16-3*2))'def zhengli(func):    func = func.replace("+-","-").replace("--","+")    return funcdef addjian(func):    func = func.strip("()")    ret = re.findall("-?\d*\.?\d+",func)    sum=0    for i in ret:        sum +=float(i)    return str(sum)def chengchu(func):    func = func.strip("()")    while("/"in func or "*" in func):        ret = re.search('\d*\.?\d+[\*/]-?\d*\.?\d',func).group()        digital = re.split('([\*/])',ret)         #加个括号是为了优先级的原因,保留非数字        result = str(float(digital[0])*float(digital[2])) if digital[1] == '*' else str(float(digital[0])/float(digital[2]))        func = func.replace(ret,result,1)        func = zhengli(func)    return funcdef comput(formal):    formal = re.sub('\s','',formal)    while(re.search('\([^()]*\)',formal)):        print(formal)        ret = re.findall('\([^()]*\)',formal)        for i in ret:            print("wu kuohao:"+i)            result_chengchu = chengchu(i) if '*'in i or '/' in i else i#先算乘除            result_addjian = addjian(result_chengchu) if '+'in result_chengchu or '-' in result_chengchu else result_chengchu#再算加减            formal = formal.replace(i,result_addjian,1)            formal = zhengli(formal)    else:        result_chengchu = chengchu(formal) if '*' in formal or '/' in formal else formal  # 先算乘除        result_addjian = addjian(result_chengchu) if '+' in result_chengchu or '-' in result_chengchu else result_chengchu  # 再算加减        return result_addjianprint(comput(formul))

 

转载于:https://www.cnblogs.com/double-t/p/10192333.html

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